3x^2-800x+8000=0

Solution for 3x^2-800x+8000=0 equation:

3x^2-800x+8000=0

a = 3; b = -800; c = +8000;
Δ = b2-4ac
Δ = -8002-4·3·8000
Δ = 544000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544000}=\sqrt{6400*85}=\sqrt{6400}*\sqrt{85}=80\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-80\sqrt{85}}{2*3}=\frac{800-80\sqrt{85}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+80\sqrt{85}}{2*3}=\frac{800+80\sqrt{85}}{6}
$